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In how many ways can at least (1) coin be selected from (8) different coins?

Answer and explanation

Correct answer: 255

Each coin has two choices: it may be selected or not selected. Hence, the total number of subsets of 8 distinct coins is \(2^8=256\). One of these is the empty selection, in which no coin is chosen. Therefore, the required number is \(256-1=255\). Thus, 255 is correct; 256 incorrectly includes the empty selection. Exam tip: for “at least one” selection questions, subtract the empty selection from the total.

Related tags

CombinationsPermutations And CombinationsClass 11SubsetsSelection CountingBinary ChoicesMathematicsClass 11 Mcq

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