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In how many ways can (4) guests be called on stage from (8) guests if their order is not considered?

Answer and explanation

Correct answer: 70

Only a selection of 4 guests from 8 is required; the order of calling them is not important. Hence, use combinations: \(\binom{8}{4}=\frac{8!}{4!\,4!}=70\). The value 1680 is \(8P_4\), which would apply if the four guests were called in a specific order. Exam tip: use \(nCr\) when order does not matter.

Related tags

CombinationsPermutations And CombinationsClass 11SelectionNcrMathematicsClass 11 Mcq

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