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Class 11MathematicsPermutations and CombinationsCombinationsEasy
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A committee has 8 members. Two distinct posts, chairperson and secretary, are to be filled. If no member can hold both posts, in how many ways can the chairperson and secretary be chosen?

Answer and explanation

Correct answer: \(56\)

Because the posts are distinct, order matters. There are 8 choices for chairperson and then 7 remaining choices for secretary, so \(8\times7=56\). \(\binom{8}{2}=28\) counts an unordered pair only. Exam tip: use permutations when positions are different.

Related tags

Permutations And CombinationsDistinct PositionsPermutationCommittee SelectionCounting PrincipleCombinationsMathematicsClass 11 Mcq
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