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In how many ways can a team of (2) doctors and (1) nurse be formed from (7) doctors and (4) nurses?

Answer and explanation

Correct answer: 84

Two doctors can be selected in \(\binom{7}{2}=21\) ways, and one nurse can be selected in \(\binom{4}{1}=4\) ways. Since these selections are independent, the multiplication principle gives \(\binom{7}{2}\binom{4}{1}=21\times4=84\) teams. The option \(56\) does not correctly combine the selections of doctors and nurses. Exam tip: when fixed numbers are chosen from separate groups, multiply the corresponding combinations.

Related tags

CombinationsPermutations And CombinationsTeam SelectionMultiplication PrincipleClass 11 MathematicsMathematicsClass 11 Mcq

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