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Find the value of (\binom{6}{2}+\binom{6}{4}).(\binom{6}{2}+\binom{6}{4}) का मान ज्ञात कीजिए।
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 3030
\(\binom{6}{2}=\frac{6!}{2!4!}=15\). Also, \(\binom{6}{4}=\binom{6}{2}=15\), using \(\binom{n}{r}=\binom{n}{n-r}\). Therefore, \(\binom{6}{2}+\binom{6}{4}=15+15=30\). Option 15 is the value of only one term, not their sum. Exam tip: use \(\binom{n}{r}=\binom{n}{n-r}\) for complementary selections.\(\binom{6}{2}=\frac{6!}{2!4!}=15\) है। साथ ही, \(\binom{6}{4}=\binom{6}{2}=15\), क्योंकि \(\binom{n}{r}=\binom{n}{n-r}\)। अतः \(\binom{6}{2}+\binom{6}{4}=15+15=30\)। विकल्प 15 केवल एक पद का मान है, योग का नहीं। परीक्षा टिप: पूरक चयन वाले पदों के लिए \(\binom{n}{r}=\binom{n}{n-r}\) का उपयोग करें।
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