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If (\binom{n}{1}+\binom{n}{0}=16), what is the value of (n)?

Answer and explanation

Correct answer: 15

Using the combination identities, \(\binom{n}{1}=n\) and \(\binom{n}{0}=1\). Thus, the given equation becomes \(n+1=16\), which gives \(n=15\). If \(n=16\), the sum would be 17, so it is not correct. Exam tip: Remember directly that \(\binom{n}{0}=1\) and \(\binom{n}{1}=n\).

Related tags

CombinationsBinomial CoefficientsClass 11 MathematicsCombination IdentitiesAlgebraic EquationsPermutations And CombinationsMathematicsClass 11 Mcq

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