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From (8) students, (4) are to be selected and two special students should not be selected together. How many ways are there?(8) विद्यार्थियों में से (4) चुनने हैं और दो विशेष विद्यार्थी साथ-साथ नहीं चुने जाने चाहिए। कितने तरीके हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (55)(55)
Total ways are (\binom{8}{4}=70), and ways with both special students are (\binom{6}{2}=15). Thus (70-15=55) ways remain.कुल (\binom{8}{4}=70) और दोनों विशेष साथ हों तो (\binom{6}{2}=15) तरीके हैं। इसलिए (70-15=55) तरीके बचेंगे।
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