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A committee of (3) members is to be formed from (9) members excluding one fixed member. How many ways are there?

Answer and explanation

Correct answer: 56

Since the fixed member cannot be included, only 8 members are available for selection. The order of members in a committee does not matter, so use combinations: \(\binom{8}{3}=\frac{8\times7\times6}{3\times2\times1}=56\). Hence, the correct answer is 56. Option 84 equals \(\binom{9}{3}\), which incorrectly includes the excluded member among the available people. Exam tip: use \(nCr\) when forming a committee because order is irrelevant.

Related tags

CombinationsCommittee SelectionExcluded MemberClass 11 MathematicsPermutations And CombinationsMathematicsClass 11 Mcq

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