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Class 11MathematicsPermutations and CombinationsCombinationsEasy
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From 6 red balls and 4 blue balls, in how many ways can 1 red and 1 blue ball be selected?

Answer and explanation

Correct answer: 24

The governing idea is independent combination selection. One red ball must be chosen from six, giving C(6,1) = 6 possibilities. Independently, one blue ball must be chosen from four, giving C(4,1) = 4 possibilities. By the multiplication principle, the total number of pairs is C(6,1) × C(4,1) = 6 × 4 = 24. Thus option C is correct. Adding 6 and 4 gives 10, but addition does not count one choice from each group. The values 20 and 30 also do not represent the product of the two independent choices. Because the balls are distinct objects, each red-blue pair is a different selection.

Related tags

CombinationsMultiplication PrincipleClass 11 MathematicsPermutations And CombinationsMathematicsClass 11 Mcq
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