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From 5 boys and 4 girls, how many ways are there to select 2 boys?

Answer and explanation

Correct answer: 10

Only the five boys are involved because the required group must contain two boys and no girls. Since a selection is a group and not an ordered arrangement, choosing Ravi and Aman is the same outcome as choosing Aman and Ravi. Therefore combinations are appropriate. The number of ways is C(5,2) = 5!/[2!3!] = (5 × 4)/(2 × 1) = 10. Thus option A is correct. If order had mattered, the calculation would have been P(5,2) = 5 × 4 = 20, which explains option B as a permutation-based distractor. The total of nine students is irrelevant because the question restricts the selection to boys only; options C and D have no valid counting basis.

Related tags

CombinationsSelectionCountingPermutationsPermutations And CombinationsMathematicsClass 11 Mcq

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