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If (x\in \mathbb{Z}), ( \frac{2x-7}{3}<5 ), and ( 4-\frac{x}{2}\leq 1 ), how many integer values of (x) are possible?यदि (x\in \mathbb{Z}), ( \frac{2x-7}{3}<5 ) और ( 4-\frac{x}{2}\leq 1 ), तो (x) के कितने पूर्णांक मान संभव हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (5)(5)
The first inequality gives (x<11), and the second gives (x\geq 6). The integers are (6,7,8,9,10), so there are (5) values.पहली असमानता से (x<11) और दूसरी से (x\geq 6) मिलता है। पूर्णांक (6,7,8,9,10) हैं, इसलिए कुल (5) मान हैं।
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