0 reads0 ratings0 helpful
If (x\in \mathbb{Z}), ( \frac{x+2}{3}\geq -1 ), and ( 2x-1<9 ), how many integer values of (x) are possible?यदि (x\in \mathbb{Z}) और ( \frac{x+2}{3}\geq -1 ) तथा ( 2x-1<9 ), तो (x) के कितने पूर्णांक मान संभव हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (8)(8)
The first inequality gives (x\geq -5), and the second gives (x<5). Integers from (-5) to (4) are (10) in total.पहली असमानता से (x\geq -5) और दूसरी से (x<5) मिलता है। पूर्णांक (-5) से (4) तक कुल (10) हैं।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
