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If ( \frac{3x-1}{2}\leq \frac{x+7}{3}<x+5 ), the correct solution for (x) is:यदि ( \frac{3x-1}{2}\leq \frac{x+7}{3}<x+5 ), तो (x) का सही हल है:
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (x\leq \frac{17}{7}) and (x>-4)(x\leq \frac{17}{7}) और (x>-4)
The first part gives (x\leq \frac{17}{7}) and the second gives (x>-4). Hence the combined solution is ((-4,\frac{17}{7}]).पहले भाग से (x\leq \frac{17}{7}) और दूसरे से (x>-4) मिलता है। अतः संयुक्त हल ((-4,\frac{17}{7}]) है।
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