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If (3(x-2)-2(x+4)\ge 5-\frac{x}{2}), what is the solution set for (x)?यदि (3(x-2)-2(x+4)\ge 5-\frac{x}{2}) है, तो (x) के लिए हल समुच्चय क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ({x:x\ge \frac{38}{3}})({x:x\ge \frac{38}{3}})
The left side is (x-14), so (x-14\ge 5-\frac{x}{2}) gives (\frac{3x}{2}\ge 19) and (x\ge \frac{38}{3}). Sign errors while opening brackets are very common in exams.बाईं ओर (x-14) है, इसलिए (x-14\ge 5-\frac{x}{2}) से (\frac{3x}{2}\ge 19) और (x\ge \frac{38}{3}) मिलता है। कोष्ठक खोलते समय संकेतों की गलती सबसे आम होती है।
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