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For integer (x), how many solutions are there for (\frac{2x-3}{5}<x-1\le\frac{x+8}{2})?

Answer and explanation

Correct answer: (11)

Solving both parts gives (x>-\frac{2}{3}) and (x\le10). Thus integers are (x=0,1,\ldots,10), totaling (11).

Related tags

Linear InequalitiesClass 11ExpertOne VariableAlgebraic Solution Of Linear Inequalities In One VariableMathematicsClass 11 Mcq

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