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How many integers (x) satisfy (\frac{2x-3}{5}<x-1\le\frac{x+8}{2})?कितने पूर्णांक (x) असमानता (\frac{2x-3}{5}<x-1\le\frac{x+8}{2}) को संतुष्ट करते हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: infinitely manyअनंत
The first part gives (x>-\frac{2}{3}), and the second gives (x\le10). Integer solutions are (0) through (10), totaling (11).पहले भाग से (x>-\frac{2}{3}) और दूसरे से (x\le10) मिलता है। पूर्णांक हल (0) से (10) तक हैं, कुल (11)।
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