0 reads0 ratings0 helpful
What is the solution of (3-\frac{x}{2}\le\frac{2x+9}{6}<5)?असमानता (3-\frac{x}{2}\le\frac{2x+9}{6}<5) का हल क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (x\ge\frac{3}{5}) and (x<\frac{21}{2})(x\ge\frac{3}{5}) और (x<\frac{21}{2})
The left inequality gives (18-3x\le2x+9), hence (x\ge\frac{9}{5}); the right gives (x<\frac{21}{2}). The correct intersection is (x\ge\frac{9}{5}) and (x<\frac{21}{2}).बाईं असमानता से (18-3x\le2x+9), अतः (x\ge\frac{9}{5}) मिलता है; दाईं से (x<\frac{21}{2})। सही प्रतिच्छेद (x\ge\frac{9}{5}) और (x<\frac{21}{2}) है।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
