Solve the compound inequality (-2\le \frac{3x+1}{5}<4).द्वि-असमीका (-2\le \frac{3x+1}{5}<4) को हल कीजिए।
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (-\frac{11}{3}\le x<\frac{19}{3})(-\frac{11}{3}\le x<\frac{19}{3})
Multiplying by (5) gives (-10\le 3x+1<20), so (-\frac{11}{3}\le x<\frac{19}{3}). A positive multiplier does not change the signs.पहले (5) से गुणा करके (-10\le 3x+1<20) मिलता है, इसलिए (-\frac{11}{3}\le x<\frac{19}{3})। परीक्षा में धनात्मक गुणा से चिन्ह नहीं बदलता।
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