Find the solution of the inequality \(\frac{3x-1}{2}\le x+4\).असमानता \(\frac{3x-1}{2}\le x+4\) का हल कीजिए।
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(x\le 9\)\(x\le 9\)
Multiply both sides by \(2\) (positive, so inequality sign stays the same):
\[\frac{3x-1}{2}\le x+4\Rightarrow 3x-1\le 2x+8\Rightarrow 3x-2x\le 8+1\Rightarrow x\le 9.\]दोनों पक्षों को \(2\) से गुणा कीजिए (धनात्मक, इसलिए असमानता का चिन्ह वही रहेगा):
\[\frac{3x-1}{2}\le x+4\Rightarrow 3x-1\le 2x+8\Rightarrow 3x-2x\le 8+1\Rightarrow x\le 9.\]
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