If x=2 satisfies the inequality \(kx+1\leq 9\) and \(k>0\), what is the required condition on \(k\)?

Correct answer: \(0<k\leq 4\)

Substituting \(x=2\) into \(kx+1\leq 9\) gives \(2k+1\leq 9\). Thus, \(2k\leq 8\), so \(k\leq 4\). Since the question also states \(k>0\), combining both conditions gives \(0<k\leq 4\). Option B is incorrect because values \(k>4\) do not satisfy the inequality. In such questions, first substitute the given value and then take the intersection of all conditions.