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What is the solution set of (9-3x\leq0)?

Answer and explanation

Correct answer: ({x:x\in\mathbb{R},x\geq3})

The inequality is 9−3x≤0. The important point is that the coefficient of x is negative. Subtracting 9 from both sides gives −3x≤−9. When both sides are divided by −3, the inequality sign must reverse because division by a negative number reverses order. This gives x≥3.

The solution set therefore contains 3 and every real number greater than 3. In set-builder form it is {x:x∈ℝ, x≥3}, which is exactly option A. The value x=3 checks the boundary because 9−3(3)=0, and 0≤0 is true. A choice using x≤3 would fail for a value such as x=4, so reversing the sign is essential.

Related tags

Linear-InequalitiesSet-BuilderNegative-Coefficient

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