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If \(x\) is an integer and \(3<2x+1\leq 13\), how many possible values of \(x\) are there?

Answer and explanation

Correct answer: 5

Subtracting 1 from all parts of \(3<2x+1\leq 13\) gives \(2<2x\leq 12\). Dividing by the positive number 2 yields \(1<x\leq 6\). Thus the integer values are \(x=2,3,4,5,6\), giving a total of 5 values. Remember that \(x=1\) is excluded, while \(x=6\) is included because the right-hand inequality uses \(\leq\).

Related tags

Compound InequalityInteger SolutionsLinear InequalitiesSolution SetCountingAlgebraic Solution Of Linear Inequalities In One VariableMathematicsClass 11 Mcq

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