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Ravi has 50 rupees. He buys notebooks at 8 rupees each and wants to save at least 10 rupees. What is the maximum number of notebooks he can buy?

Answer and explanation

Correct answer: 5

If Ravi buys x notebooks, the amount left is \(50-8x\) rupees. The condition for saving at least 10 rupees is \(50-8x\ge 10\), which gives \(x\le 5\). Therefore, the greatest possible whole number of notebooks is 5. Option 6 is incorrect because buying 6 notebooks costs 48 rupees and leaves only 2 rupees. Exam tip: Form the inequality first, then choose the greatest feasible whole-number value.

Related tags

Word ProblemLinear InequalityMaximum IntegerAlgebraic Solution Of Linear Inequalities In One VariableLinear InequalitiesMathematicsClass 11 Mcq

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