If 5 is subtracted from three times a number and the result is at least 16, what is the solution for the number?

Correct answer: \(x\geq 7\)

Let the number be \(x\). The inequality is \(3x-5\geq 16\). Adding 5 to both sides gives \(3x\geq 21\), and dividing by 3 gives \(x\geq 7\). Therefore, option A is correct. Option B reverses the inequality incorrectly, while option C excludes the value \(x=7\), even though ‘at least’ includes equality. Exam tip: ‘at least’ means \(\geq\), whereas ‘greater than’ means \(>\).