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If (x) is a whole number and (x\le 3), what is the solution set?

Answer and explanation

Correct answer: \({0,1,2,3}\)

The direct answer is A: \(\{0,1,2,3\}\). In school mathematics, whole numbers are the non-negative integers: \(0,1,2,3,\ldots\). The condition \(x\le3\) keeps every whole number from 0 through 3 and excludes 4 and all larger numbers. Thus the finite answer set is \(\{0,1,2,3\}\). Option A is correct. Option B, \(\{1,2,3\}\), wrongly omits 0; 0 is a whole number and satisfies \(0\le3\). Option C, \(\{0,1,2\}\), wrongly omits 3, which is allowed because the sign is \(\le\), not \(<\). Option D, \(\{3,4,5\}\), includes numbers greater than 3 and therefore violates the condition, although it includes 3. The phrase whole number is important: it starts at 0, unlike positive counting numbers, which usually start at 1. Memory cue: whole numbers are 0 and the counting numbers; with \(\le3\), stop at and include 3.

Related tags

Linear InequalitiesWhole NumbersSolution Set

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