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What is the solution of the inequality \(3(2x-5)\geq x+10\)?असमानता \(3(2x-5)\geq x+10\) का हल क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(x\geq 5\)\(x\geq 5\)
Expanding the bracket gives \(6x-15\geq x+10\). Subtracting \(x\) from both sides gives \(5x-15\geq 10\), or \(5x\geq 25\), so \(x\geq 5\). Remember that dividing an inequality by a positive number does not reverse its sign.कोष्ठक खोलने पर \(6x-15\geq x+10\) मिलता है। दोनों पक्षों से \(x\) घटाने पर \(5x-15\geq 10\), अर्थात \(5x\geq 25\), इसलिए \(x\geq 5\)। ध्यान रखें कि धनात्मक संख्या से भाग देने पर असमानता का चिह्न नहीं बदलता।
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