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If \(\frac{x+3}{2}>6\), what is the least integer value of \(x\)?

Answer and explanation

Correct answer: 10

Multiplying \(\frac{x+3}{2}>6\) by 2 gives \(x+3>12\), so \(x>9\). The smallest integer greater than 9 is 10. Therefore, the correct answer is 10. Remember that the strict sign ‘>’ excludes 9; with ‘\(\geq\)’, 9 would also be included.

Related tags

Linear InequalitiesStrict InequalitiesInteger SolutionsClass 11 MathematicsAlgebraic Solution Of Linear Inequalities In One VariableMathematicsClass 11 Mcq

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