अव्यवस्थित जोड़े गिनने में \(^{n}P_2\) को (2!) से क्यों भाग देते हैं?
Why is \(^{n}P_2\) divided by (2!) while counting unordered pairs?
Explanation opens after your attempt
Correct Answer
A. क्योंकि हर जोड़ा (2!) क्रमों में गिना जाता हैBecause each pair is counted in (2!) orders
Concept
The pair (AB) and (BA) is considered same so we divide by (2!). In exams remove overcounting when unordered appears.
Why this answer is correct
The correct answer is A. क्योंकि हर जोड़ा (2!) क्रमों में गिना जाता है / Because each pair is counted in (2!) orders. The pair (AB) and (BA) is considered same so we divide by (2!). In exams remove overcounting when unordered appears.
Exam Tip
जोड़ा (AB) और (BA) समान माना जाता है इसलिए (2!) से भाग देते हैं। परीक्षा में unordered शब्द आते ही दोहराव हटाएँ।
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