कौन सा कथन \(x^2+2<0\) के लिए सही है?

Which statement is correct for \(x^2+2<0\)?

Explanation opens after your attempt
Correct Answer

A. कोई वास्तविक हल नहींno real solution

Step 1

Concept

For every real (x), \(x^2\ge 0\), so \(x^2+2\ge 2\). It can never be less than (0).

Step 2

Why this answer is correct

The correct answer is A. कोई वास्तविक हल नहीं / no real solution. For every real (x), \(x^2\ge 0\), so \(x^2+2\ge 2\). It can never be less than (0).

Step 3

Exam Tip

हर वास्तविक (x) के लिए \(x^2\ge 0\), इसलिए \(x^2+2\ge 2\) होगा। यह कभी (0) से छोटा नहीं हो सकता।

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FAQs

Mathematics Answer, Explanation and Revision Hints

कौन सा कथन \(x^2+2<0\) के लिए सही है? / Which statement is correct for \(x^2+2<0\)?

Correct Answer: A. कोई वास्तविक हल नहीं / no real solution. Explanation: हर वास्तविक (x) के लिए \(x^2\ge 0\), इसलिए \(x^2+2\ge 2\) होगा। यह कभी (0) से छोटा नहीं हो सकता। / For every real (x), \(x^2\ge 0\), so \(x^2+2\ge 2\). It can never be less than (0).

Which concept should I revise for this Mathematics MCQ?

For every real (x), \(x^2\ge 0\), so \(x^2+2\ge 2\). It can never be less than (0).

What exam hint can help solve this Mathematics question?

हर वास्तविक (x) के लिए \(x^2\ge 0\), इसलिए \(x^2+2\ge 2\) होगा। यह कभी (0) से छोटा नहीं हो सकता।