किस विकल्प में \(x^2\le0\) का वास्तविक हल सही है?

Which option gives the correct real solution of \(x^2\le0\)?

Explanation opens after your attempt
Correct Answer

A. ({0})

Step 1

Concept

Both \(x^2\le0\) and \(x^2\ge0\) are possible only when (x=0). In exams check the equality case separately.

Step 2

Why this answer is correct

The correct answer is A. ({0}). Both \(x^2\le0\) and \(x^2\ge0\) are possible only when (x=0). In exams check the equality case separately.

Step 3

Exam Tip

\(x^2\le0\) और \(x^2\ge0\) दोनों तभी संभव हैं जब (x=0)। परीक्षा में बराबरी का मामला अलग जांचें।

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Mathematics Answer, Explanation and Revision Hints

किस विकल्प में \(x^2\le0\) का वास्तविक हल सही है? / Which option gives the correct real solution of \(x^2\le0\)?

Correct Answer: A. ({0}). Explanation: \(x^2\le0\) और \(x^2\ge0\) दोनों तभी संभव हैं जब (x=0)। परीक्षा में बराबरी का मामला अलग जांचें। / Both \(x^2\le0\) and \(x^2\ge0\) are possible only when (x=0). In exams check the equality case separately.

Which concept should I revise for this Mathematics MCQ?

Both \(x^2\le0\) and \(x^2\ge0\) are possible only when (x=0). In exams check the equality case separately.

What exam hint can help solve this Mathematics question?

\(x^2\le0\) और \(x^2\ge0\) दोनों तभी संभव हैं जब (x=0)। परीक्षा में बराबरी का मामला अलग जांचें।