\(^{n}C_3\) का सरलीकृत रूप कौन-सा है?
Which is the simplified form of \(^{n}C_3\)?
Explanation opens after your attempt
Correct Answer
B. (\frac{n(n-1)(n-2)}{6})
Concept
From (^{n}C_3=\frac{n!}{3!(n-3)!}) the numerator becomes (n(n-1)(n-2)) and denominator (6). In exams remember (3!=6).
Why this answer is correct
The correct answer is B. (\frac{n(n-1)(n-2)}{6}). From (^{n}C_3=\frac{n!}{3!(n-3)!}) the numerator becomes (n(n-1)(n-2)) and denominator (6). In exams remember (3!=6).
Exam Tip
(^{n}C_3=\frac{n!}{3!(n-3)!}) से ऊपर (n(n-1)(n-2)) और नीचे (6) बचता है। परीक्षा में (3!=6) याद रखें।
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