असमानता \(\frac{11-3x}{2}\ge -5\) का संख्या रेखा पर हल कौन-सा है?
Which is the number line solution of \(\frac{11-3x}{2}\ge -5\)?
Explanation opens after your attempt
A. \(x\le7\), (7) पर बंद बिंदु और बाईं ओर\(x\le7\), closed dot at (7) shaded left
Concept
\(11-3x\ge-10\) gives \(-3x\ge-21\), so \(x\le7\). In exams, reverse the inequality while dividing by a negative.
Why this answer is correct
The correct answer is A. \(x\le7\), (7) पर बंद बिंदु और बाईं ओर / \(x\le7\), closed dot at (7) shaded left. \(11-3x\ge-10\) gives \(-3x\ge-21\), so \(x\le7\). In exams, reverse the inequality while dividing by a negative.
Exam Tip
\(11-3x\ge-10\) से \(-3x\ge-21\), इसलिए \(x\le7\)। परीक्षा में ऋणात्मक से divide करते समय inequality reverse करें।
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