असमानता (3(5-x)\le 2x+20) का संख्या रेखा हल कौन-सा है?
Which is the number line solution of (3(5-x)\le 2x+20)?
Explanation opens after your attempt
A. \(x\ge -1\), (-1) पर बंद बिंदु और दाईं ओर\(x\ge -1\), closed dot at (-1) shaded right
Concept
\(15-3x\le2x+20\) gives \(-5\le5x\), so \(x\ge-1\). In exams, write the final inequality in the standard direction.
Why this answer is correct
The correct answer is A. \(x\ge -1\), (-1) पर बंद बिंदु और दाईं ओर / \(x\ge -1\), closed dot at (-1) shaded right. \(15-3x\le2x+20\) gives \(-5\le5x\), so \(x\ge-1\). In exams, write the final inequality in the standard direction.
Exam Tip
\(15-3x\le2x+20\) से \(-5\le5x\), इसलिए \(x\ge-1\)। परीक्षा में final inequality को standard direction में लिखें।
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