असमानता (3(5-x)\le 2x+20) का संख्या रेखा हल कौन-सा है?

Which is the number line solution of (3(5-x)\le 2x+20)?

Explanation opens after your attempt
Correct Answer

A. \(x\ge -1\), (-1) पर बंद बिंदु और दाईं ओर\(x\ge -1\), closed dot at (-1) shaded right

Step 1

Concept

\(15-3x\le2x+20\) gives \(-5\le5x\), so \(x\ge-1\). In exams, write the final inequality in the standard direction.

Step 2

Why this answer is correct

The correct answer is A. \(x\ge -1\), (-1) पर बंद बिंदु और दाईं ओर / \(x\ge -1\), closed dot at (-1) shaded right. \(15-3x\le2x+20\) gives \(-5\le5x\), so \(x\ge-1\). In exams, write the final inequality in the standard direction.

Step 3

Exam Tip

\(15-3x\le2x+20\) से \(-5\le5x\), इसलिए \(x\ge-1\)। परीक्षा में final inequality को standard direction में लिखें।

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Mathematics Answer, Explanation and Revision Hints

असमानता (3(5-x)\le 2x+20) का संख्या रेखा हल कौन-सा है? / Which is the number line solution of (3(5-x)\le 2x+20)?

Correct Answer: A. \(x\ge -1\), (-1) पर बंद बिंदु और दाईं ओर / \(x\ge -1\), closed dot at (-1) shaded right. Explanation: \(15-3x\le2x+20\) से \(-5\le5x\), इसलिए \(x\ge-1\)। परीक्षा में final inequality को standard direction में लिखें। / \(15-3x\le2x+20\) gives \(-5\le5x\), so \(x\ge-1\). In exams, write the final inequality in the standard direction.

Which concept should I revise for this Mathematics MCQ?

\(15-3x\le2x+20\) gives \(-5\le5x\), so \(x\ge-1\). In exams, write the final inequality in the standard direction.

What exam hint can help solve this Mathematics question?

\(15-3x\le2x+20\) से \(-5\le5x\), इसलिए \(x\ge-1\)। परीक्षा में final inequality को standard direction में लिखें।