ग्राफ \(y=\frac{1}{x+2}-1\) की क्षैतिज असिम्पटोट कौन-सी है?
Which is the horizontal asymptote of the graph \(y=\frac{1}{x+2}-1\)?
Explanation opens after your attempt
Correct Answer
A. (y=-1)
Concept
For large (|x|), \(\frac{1}{x+2}\) approaches (0), so (y=-1). The outside constant shifts the horizontal asymptote.
Why this answer is correct
The correct answer is A. (y=-1). For large (|x|), \(\frac{1}{x+2}\) approaches (0), so (y=-1). The outside constant shifts the horizontal asymptote.
Exam Tip
\(\frac{1}{x+2}\) बहुत बड़े (|x|) पर (0) के निकट जाता है, इसलिए (y=-1)। बाहरी स्थिरांक क्षैतिज असिम्पटोट बदलता है।
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