Class 11 Mathematics Linear Inequalities representation on number line Hard Level 48

असमानता \(|4x+1|\le 9\) का संख्या रेखा पर सही interval कौन-सा है?

Which is the correct interval on the number line for \(|4x+1|\le 9\)?

Explanation opens after your attempt
Correct Answer

C. \([-\frac{5}{2},2]\)

Step 1

Concept

\(-9\le4x+1\le9\) gives \(-10\le4x\le8\), so \(-\frac{5}{2}\le x\le2\). In exams, modulus with \(\le\) gives a closed interval.

Step 2

Why this answer is correct

The correct answer is C. \([-\frac{5}{2},2]\). \(-9\le4x+1\le9\) gives \(-10\le4x\le8\), so \(-\frac{5}{2}\le x\le2\). In exams, modulus with \(\le\) gives a closed interval.

Step 3

Exam Tip

\(-9\le4x+1\le9\) से \(-10\le4x\le8\), इसलिए \(-\frac{5}{2}\le x\le2\)। परीक्षा में \(\le\) वाले modulus में closed interval लें।

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असमानता \(|4x+1|\le 9\) का संख्या रेखा पर सही interval कौन-सा है? / Which is the correct interval on the number line for \(|4x+1|\le 9\)?

Correct Answer: C. \([-\frac{5}{2},2]\). Explanation: \(-9\le4x+1\le9\) से \(-10\le4x\le8\), इसलिए \(-\frac{5}{2}\le x\le2\)। परीक्षा में \(\le\) वाले modulus में closed interval लें। / \(-9\le4x+1\le9\) gives \(-10\le4x\le8\), so \(-\frac{5}{2}\le x\le2\). In exams, modulus with \(\le\) gives a closed interval.

Which concept should I revise for this Mathematics MCQ?

\(-9\le4x+1\le9\) gives \(-10\le4x\le8\), so \(-\frac{5}{2}\le x\le2\). In exams, modulus with \(\le\) gives a closed interval.

What exam hint can help solve this Mathematics question?

\(-9\le4x+1\le9\) से \(-10\le4x\le8\), इसलिए \(-\frac{5}{2}\le x\le2\)। परीक्षा में \(\le\) वाले modulus में closed interval लें।