( \frac{(2n)!}{(2n-3)!} ) का सही विस्तार कौन सा है?

Which is the correct expansion of ( \frac{(2n)!}{(2n-3)!} )?

Explanation opens after your attempt
Correct Answer

C. ( (2n)(2n-1)(2n-2) )

Step 1

Concept

We expand ((2n)!) up to ((2n)(2n-1)(2n-2)(2n-3)!). Therefore, three factors remain.

Step 2

Why this answer is correct

The correct answer is C. ( (2n)(2n-1)(2n-2) ). We expand ((2n)!) up to ((2n)(2n-1)(2n-2)(2n-3)!). Therefore, three factors remain.

Step 3

Exam Tip

((2n)!) को ((2n)(2n-1)(2n-2)(2n-3)!) तक फैलाते हैं। इसलिए तीन गुणक शेष रहते हैं।

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Mathematics Answer, Explanation and Revision Hints

( \frac{(2n)!}{(2n-3)!} ) का सही विस्तार कौन सा है? / Which is the correct expansion of ( \frac{(2n)!}{(2n-3)!} )?

Correct Answer: C. ( (2n)(2n-1)(2n-2) ). Explanation: ((2n)!) को ((2n)(2n-1)(2n-2)(2n-3)!) तक फैलाते हैं। इसलिए तीन गुणक शेष रहते हैं। / We expand ((2n)!) up to ((2n)(2n-1)(2n-2)(2n-3)!). Therefore, three factors remain.

Which concept should I revise for this Mathematics MCQ?

We expand ((2n)!) up to ((2n)(2n-1)(2n-2)(2n-3)!). Therefore, three factors remain.

What exam hint can help solve this Mathematics question?

((2n)!) को ((2n)(2n-1)(2n-2)(2n-3)!) तक फैलाते हैं। इसलिए तीन गुणक शेष रहते हैं।