असमानता \(4-2x\le 10\) के लिए संख्या रेखा पर सही interval कौन-सा है?
Which interval is correct on the number line for \(4-2x\le 10\)?
Explanation opens after your attempt
A. \([-3,\infty\))
Concept
\(4-2x\le 10\) gives \(-2x\le 6\), so \(x\ge -3\). In exams, reverse the sign when dividing by a negative.
Why this answer is correct
The correct answer is A. \([-3,\infty\)). \(4-2x\le 10\) gives \(-2x\le 6\), so \(x\ge -3\). In exams, reverse the sign when dividing by a negative.
Exam Tip
\(4-2x\le 10\) से \(-2x\le 6\), इसलिए \(x\ge -3\) है। परीक्षा में ऋणात्मक भाग देने पर sign reverse करें।
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