असमानता \(2y+x\ge 14\) को (y) के रूप में लिखने पर कौन-सा रूप सही है?
Which form is correct when \(2y+x\ge 14\) is written in terms of (y)?
Explanation opens after your attempt
Correct Answer
B. \(y\ge \frac{14-x}{2}\)
Concept
From \(2y+x\ge 14\), we get \(2y\ge 14-x\). Hence \(y\ge \frac{14-x}{2}\) is correct.
Why this answer is correct
The correct answer is B. \(y\ge \frac{14-x}{2}\). From \(2y+x\ge 14\), we get \(2y\ge 14-x\). Hence \(y\ge \frac{14-x}{2}\) is correct.
Exam Tip
\(2y+x\ge 14\) से \(2y\ge 14-x\) मिलता है। इसलिए \(y\ge \frac{14-x}{2}\) सही है।
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