फलन \(y=\sin x\) का \(0\le x\le2\pi\) में अधिकतम मान कहाँ मिलता है?
Where does \(y=\sin x\) attain its maximum on \(0\le x\le2\pi\)?
Explanation opens after your attempt
Correct Answer
A. \(x=\frac{\pi}{2}\)
Concept
The maximum of \(\sin x\) is (1), attained at \(x=\frac{\pi}{2}\). Remember key points of standard trigonometric graphs.
Why this answer is correct
The correct answer is A. \(x=\frac{\pi}{2}\). The maximum of \(\sin x\) is (1), attained at \(x=\frac{\pi}{2}\). Remember key points of standard trigonometric graphs.
Exam Tip
\(\sin x\) का अधिकतम मान (1) होता है, जो \(x=\frac{\pi}{2}\) पर मिलता है। मानक त्रिकोणमितीय ग्राफ के मुख्य बिंदु याद रखें।
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