असमानता (4x+1<4x+9) का हल कौन सा है?

What is the solution of (4x+1<4x+9)?

Explanation opens after your attempt
Correct Answer

A. सभी \(x\in\mathbb{R}\)all \(x\in\mathbb{R}\)

Step 1

Concept

Subtracting (4x) from both sides gives (1<9), which is always true. When the variable cancels, decide the solution from the truth of the remaining statement.

Step 2

Why this answer is correct

The correct answer is A. सभी \(x\in\mathbb{R}\) / all \(x\in\mathbb{R}\). Subtracting (4x) from both sides gives (1<9), which is always true. When the variable cancels, decide the solution from the truth of the remaining statement.

Step 3

Exam Tip

दोनों पक्षों से (4x) घटाने पर (1<9) मिलता है, जो हमेशा सत्य है। चर हटने पर शेष कथन की सत्यता से हल तय करें।

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Mathematics Answer, Explanation and Revision Hints

असमानता (4x+1<4x+9) का हल कौन सा है? / What is the solution of (4x+1<4x+9)?

Correct Answer: A. सभी \(x\in\mathbb{R}\) / all \(x\in\mathbb{R}\). Explanation: दोनों पक्षों से (4x) घटाने पर (1<9) मिलता है, जो हमेशा सत्य है। चर हटने पर शेष कथन की सत्यता से हल तय करें। / Subtracting (4x) from both sides gives (1<9), which is always true. When the variable cancels, decide the solution from the truth of the remaining statement.

Which concept should I revise for this Mathematics MCQ?

Subtracting (4x) from both sides gives (1<9), which is always true. When the variable cancels, decide the solution from the truth of the remaining statement.

What exam hint can help solve this Mathematics question?

दोनों पक्षों से (4x) घटाने पर (1<9) मिलता है, जो हमेशा सत्य है। चर हटने पर शेष कथन की सत्यता से हल तय करें।