असमानता (-3(x+2)+7\ge 2(4-x)-5) का हल क्या है?

What is the solution of (-3(x+2)+7\ge 2(4-x)-5)?

Explanation opens after your attempt
Correct Answer

A. \(x\le -2\)

Step 1

Concept

Simplification gives \(1-3x\ge 3-2x\). Thus \(-2\ge x\), i.e. \(x\le -2\).

Step 2

Why this answer is correct

The correct answer is A. \(x\le -2\). Simplification gives \(1-3x\ge 3-2x\). Thus \(-2\ge x\), i.e. \(x\le -2\).

Step 3

Exam Tip

सरलीकरण से \(1-3x\ge 3-2x\) मिलता है। इससे \(-2\ge x\), यानी \(x\le -2\)।

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Mathematics Answer, Explanation and Revision Hints

असमानता (-3(x+2)+7\ge 2(4-x)-5) का हल क्या है? / What is the solution of (-3(x+2)+7\ge 2(4-x)-5)?

Correct Answer: A. \(x\le -2\). Explanation: सरलीकरण से \(1-3x\ge 3-2x\) मिलता है। इससे \(-2\ge x\), यानी \(x\le -2\)। / Simplification gives \(1-3x\ge 3-2x\). Thus \(-2\ge x\), i.e. \(x\le -2\).

Which concept should I revise for this Mathematics MCQ?

Simplification gives \(1-3x\ge 3-2x\). Thus \(-2\ge x\), i.e. \(x\le -2\).

What exam hint can help solve this Mathematics question?

सरलीकरण से \(1-3x\ge 3-2x\) मिलता है। इससे \(-2\ge x\), यानी \(x\le -2\)।