( \frac{(n+7)!}{(n+4)!}-\frac{(n+6)!}{(n+3)!} ) का सरल रूप क्या है?

What is the simplified form of ( \frac{(n+7)!}{(n+4)!}-\frac{(n+6)!}{(n+3)!} )?

Explanation opens after your attempt
Correct Answer

B. (4(n+6)(n+5))

Step 1

Concept

Take common ((n+6)(n+5)). The difference is ((n+7)-(n+4)=3), so the correct form is (3(n+6)(n+5)).

Step 2

Why this answer is correct

The correct answer is B. (4(n+6)(n+5)). Take common ((n+6)(n+5)). The difference is ((n+7)-(n+4)=3), so the correct form is (3(n+6)(n+5)).

Step 3

Exam Tip

सामान्य ((n+6)(n+5)) निकालें। अंतर ((n+7)-(n+4)=3) नहीं, क्योंकि दूसरा पद ((n+6)(n+5)(n+4)) है और अंतर (3(n+6)(n+5)) है।

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Mathematics Answer, Explanation and Revision Hints

( \frac{(n+7)!}{(n+4)!}-\frac{(n+6)!}{(n+3)!} ) का सरल रूप क्या है? / What is the simplified form of ( \frac{(n+7)!}{(n+4)!}-\frac{(n+6)!}{(n+3)!} )?

Correct Answer: B. (4(n+6)(n+5)). Explanation: सामान्य ((n+6)(n+5)) निकालें। अंतर ((n+7)-(n+4)=3) नहीं, क्योंकि दूसरा पद ((n+6)(n+5)(n+4)) है और अंतर (3(n+6)(n+5)) है। / Take common ((n+6)(n+5)). The difference is ((n+7)-(n+4)=3), so the correct form is (3(n+6)(n+5)).

Which concept should I revise for this Mathematics MCQ?

Take common ((n+6)(n+5)). The difference is ((n+7)-(n+4)=3), so the correct form is (3(n+6)(n+5)).

What exam hint can help solve this Mathematics question?

सामान्य ((n+6)(n+5)) निकालें। अंतर ((n+7)-(n+4)=3) नहीं, क्योंकि दूसरा पद ((n+6)(n+5)(n+4)) है और अंतर (3(n+6)(n+5)) है।