( \frac{(n+4)!-(n+3)!}{(n+2)!} ) का सरल रूप क्या है?

What is the simplified form of ( \frac{(n+4)!-(n+3)!}{(n+2)!} )?

Explanation opens after your attempt
Correct Answer

A. ((n+3)2)

Step 1

Concept

((n+4)!-(n+3)!=(n+3)!((n+4)-1)). Therefore ((n+3)2) is obtained.

Step 2

Why this answer is correct

The correct answer is A. ((n+3)2). ((n+4)!-(n+3)!=(n+3)!((n+4)-1)). Therefore ((n+3)2) is obtained.

Step 3

Exam Tip

((n+4)!-(n+3)!=(n+3)!((n+4)-1)) है। इसलिए ((n+3)2) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

( \frac{(n+4)!-(n+3)!}{(n+2)!} ) का सरल रूप क्या है? / What is the simplified form of ( \frac{(n+4)!-(n+3)!}{(n+2)!} )?

Correct Answer: A. ((n+3)2). Explanation: ((n+4)!-(n+3)!=(n+3)!((n+4)-1)) है। इसलिए ((n+3)2) मिलता है। / ((n+4)!-(n+3)!=(n+3)!((n+4)-1)). Therefore ((n+3)2) is obtained.

Which concept should I revise for this Mathematics MCQ?

((n+4)!-(n+3)!=(n+3)!((n+4)-1)). Therefore ((n+3)2) is obtained.

What exam hint can help solve this Mathematics question?

((n+4)!-(n+3)!=(n+3)!((n+4)-1)) है। इसलिए ((n+3)2) मिलता है।