( \frac{(n+4)!+(n+3)!}{(n+2)!} ) का सरल रूप क्या है?

What is the simplified form of ( \frac{(n+4)!+(n+3)!}{(n+2)!} )?

Explanation opens after your attempt
Correct Answer

A. ( (n+3)(n+5) )

Step 1

Concept

Taking ((n+3)!) common gives ((n+3)!(n+5)) in the numerator. Dividing gives ((n+3)(n+5)).

Step 2

Why this answer is correct

The correct answer is A. ( (n+3)(n+5) ). Taking ((n+3)!) common gives ((n+3)!(n+5)) in the numerator. Dividing gives ((n+3)(n+5)).

Step 3

Exam Tip

((n+3)!) सामान्य लेने पर ऊपर ((n+3)!(n+5)) बनता है। भाग देने पर ((n+3)(n+5)) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

( \frac{(n+4)!+(n+3)!}{(n+2)!} ) का सरल रूप क्या है? / What is the simplified form of ( \frac{(n+4)!+(n+3)!}{(n+2)!} )?

Correct Answer: A. ( (n+3)(n+5) ). Explanation: ((n+3)!) सामान्य लेने पर ऊपर ((n+3)!(n+5)) बनता है। भाग देने पर ((n+3)(n+5)) मिलता है। / Taking ((n+3)!) common gives ((n+3)!(n+5)) in the numerator. Dividing gives ((n+3)(n+5)).

Which concept should I revise for this Mathematics MCQ?

Taking ((n+3)!) common gives ((n+3)!(n+5)) in the numerator. Dividing gives ((n+3)(n+5)).

What exam hint can help solve this Mathematics question?

((n+3)!) सामान्य लेने पर ऊपर ((n+3)!(n+5)) बनता है। भाग देने पर ((n+3)(n+5)) मिलता है।