( \frac{(n+4)!}{(n+1)!}+\frac{(n+3)!}{n!} ) का सरल रूप क्या है?

What is the simplified form of ( \frac{(n+4)!}{(n+1)!}+\frac{(n+3)!}{n!} )?

Explanation opens after your attempt
Correct Answer

C. ( (n+3)(n+2)(2n+5) )

Step 1

Concept

The common factor in both terms is ( (n+3)(n+2) ). Therefore the simplified form is ( (n+3)(n+2)(2n+5) ).

Step 2

Why this answer is correct

The correct answer is C. ( (n+3)(n+2)(2n+5) ). The common factor in both terms is ( (n+3)(n+2) ). Therefore the simplified form is ( (n+3)(n+2)(2n+5) ).

Step 3

Exam Tip

दोनों पदों में ( (n+3)(n+2) ) सामान्य है। इसलिए सरल रूप ( (n+3)(n+2)(2n+5) ) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

( \frac{(n+4)!}{(n+1)!}+\frac{(n+3)!}{n!} ) का सरल रूप क्या है? / What is the simplified form of ( \frac{(n+4)!}{(n+1)!}+\frac{(n+3)!}{n!} )?

Correct Answer: C. ( (n+3)(n+2)(2n+5) ). Explanation: दोनों पदों में ( (n+3)(n+2) ) सामान्य है। इसलिए सरल रूप ( (n+3)(n+2)(2n+5) ) मिलता है। / The common factor in both terms is ( (n+3)(n+2) ). Therefore the simplified form is ( (n+3)(n+2)(2n+5) ).

Which concept should I revise for this Mathematics MCQ?

The common factor in both terms is ( (n+3)(n+2) ). Therefore the simplified form is ( (n+3)(n+2)(2n+5) ).

What exam hint can help solve this Mathematics question?

दोनों पदों में ( (n+3)(n+2) ) सामान्य है। इसलिए सरल रूप ( (n+3)(n+2)(2n+5) ) मिलता है।