( \frac{(n+3)!}{(n-1)!(n+2)(n+1)} ) का सरल रूप क्या है?

What is the simplified form of ( \frac{(n+3)!}{(n-1)!(n+2)(n+1)} )?

Explanation opens after your attempt
Correct Answer

A. (n(n+3))

Step 1

Concept

The numerator is ((n+3)(n+2)(n+1)n(n-1)!). After cancellation, (n(n+3)) remains.

Step 2

Why this answer is correct

The correct answer is A. (n(n+3)). The numerator is ((n+3)(n+2)(n+1)n(n-1)!). After cancellation, (n(n+3)) remains.

Step 3

Exam Tip

ऊपर ((n+3)(n+2)(n+1)n(n-1)!) है। काटने पर (n(n+3)) बचता है।

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Mathematics Answer, Explanation and Revision Hints

( \frac{(n+3)!}{(n-1)!(n+2)(n+1)} ) का सरल रूप क्या है? / What is the simplified form of ( \frac{(n+3)!}{(n-1)!(n+2)(n+1)} )?

Correct Answer: A. (n(n+3)). Explanation: ऊपर ((n+3)(n+2)(n+1)n(n-1)!) है। काटने पर (n(n+3)) बचता है। / The numerator is ((n+3)(n+2)(n+1)n(n-1)!). After cancellation, (n(n+3)) remains.

Which concept should I revise for this Mathematics MCQ?

The numerator is ((n+3)(n+2)(n+1)n(n-1)!). After cancellation, (n(n+3)) remains.

What exam hint can help solve this Mathematics question?

ऊपर ((n+3)(n+2)(n+1)n(n-1)!) है। काटने पर (n(n+3)) बचता है।