( \frac{(n!)2}{(n-2)!(n+2)!} ) का सरल रूप क्या है?

What is the simplified form of ( \frac{(n!)2}{(n-2)!(n+2)!} )?

Explanation opens after your attempt
Correct Answer

B. ( \frac{n(n-1)}{(n+1)(n+2)} )

Step 1

Concept

( \frac{n!}{(n-2)!}=n(n-1) ) and ( \frac{n!}{(n+2)!}=\frac{1}{(n+2)(n+1)} ), so the answer follows. Break the ratio into two parts.

Step 2

Why this answer is correct

The correct answer is B. ( \frac{n(n-1)}{(n+1)(n+2)} ). ( \frac{n!}{(n-2)!}=n(n-1) ) and ( \frac{n!}{(n+2)!}=\frac{1}{(n+2)(n+1)} ), so the answer follows. Break the ratio into two parts.

Step 3

Exam Tip

( \frac{n!}{(n-2)!}=n(n-1) ) और ( \frac{n!}{(n+2)!}=\frac{1}{(n+2)(n+1)} ), इसलिए उत्तर मिलता है। अनुपात को दो भागों में तोड़ें।

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Mathematics Answer, Explanation and Revision Hints

( \frac{(n!)2}{(n-2)!(n+2)!} ) का सरल रूप क्या है? / What is the simplified form of ( \frac{(n!)2}{(n-2)!(n+2)!} )?

Correct Answer: B. ( \frac{n(n-1)}{(n+1)(n+2)} ). Explanation: ( \frac{n!}{(n-2)!}=n(n-1) ) और ( \frac{n!}{(n+2)!}=\frac{1}{(n+2)(n+1)} ), इसलिए उत्तर मिलता है। अनुपात को दो भागों में तोड़ें। / ( \frac{n!}{(n-2)!}=n(n-1) ) and ( \frac{n!}{(n+2)!}=\frac{1}{(n+2)(n+1)} ), so the answer follows. Break the ratio into two parts.

Which concept should I revise for this Mathematics MCQ?

( \frac{n!}{(n-2)!}=n(n-1) ) and ( \frac{n!}{(n+2)!}=\frac{1}{(n+2)(n+1)} ), so the answer follows. Break the ratio into two parts.

What exam hint can help solve this Mathematics question?

( \frac{n!}{(n-2)!}=n(n-1) ) और ( \frac{n!}{(n+2)!}=\frac{1}{(n+2)(n+1)} ), इसलिए उत्तर मिलता है। अनुपात को दो भागों में तोड़ें।