( \frac{\frac{(n+3)!}{n!}}{n+3} ) का सरल रूप क्या है?

What is the simplified form of ( \frac{\frac{(n+3)!}{n!}}{n+3} )?

Explanation opens after your attempt
Correct Answer

D. ( (n+2)(n+1) )

Step 1

Concept

The upper ratio is ((n+3)(n+2)(n+1)). Dividing by (n+3) leaves ((n+2)(n+1)).

Step 2

Why this answer is correct

The correct answer is D. ( (n+2)(n+1) ). The upper ratio is ((n+3)(n+2)(n+1)). Dividing by (n+3) leaves ((n+2)(n+1)).

Step 3

Exam Tip

ऊपर का अनुपात ((n+3)(n+2)(n+1)) है। (n+3) से भाग देने पर ((n+2)(n+1)) बचता है।

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Mathematics Answer, Explanation and Revision Hints

( \frac{\frac{(n+3)!}{n!}}{n+3} ) का सरल रूप क्या है? / What is the simplified form of ( \frac{\frac{(n+3)!}{n!}}{n+3} )?

Correct Answer: D. ( (n+2)(n+1) ). Explanation: ऊपर का अनुपात ((n+3)(n+2)(n+1)) है। (n+3) से भाग देने पर ((n+2)(n+1)) बचता है। / The upper ratio is ((n+3)(n+2)(n+1)). Dividing by (n+3) leaves ((n+2)(n+1)).

Which concept should I revise for this Mathematics MCQ?

The upper ratio is ((n+3)(n+2)(n+1)). Dividing by (n+3) leaves ((n+2)(n+1)).

What exam hint can help solve this Mathematics question?

ऊपर का अनुपात ((n+3)(n+2)(n+1)) है। (n+3) से भाग देने पर ((n+2)(n+1)) बचता है।