( \frac{\frac{(n+3)!}{(n-2)!}}{\frac{(n+2)!}{(n-3)!}} ) का सरल रूप क्या है?

What is the simplified form of ( \frac{\frac{(n+3)!}{(n-2)!}}{\frac{(n+2)!}{(n-3)!}} )?

Explanation opens after your attempt
Correct Answer

A. \( \frac{n+3}{n-2} \)

Step 1

Concept

The common factors of both large ratios cancel out. Finally \( \frac{n+3}{n-2} \) remains.

Step 2

Why this answer is correct

The correct answer is A. \( \frac{n+3}{n-2} \). The common factors of both large ratios cancel out. Finally \( \frac{n+3}{n-2} \) remains.

Step 3

Exam Tip

दोनों बड़े अनुपातों के समान गुणक कट जाते हैं। अंत में \( \frac{n+3}{n-2} \) बचता है।

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Mathematics Answer, Explanation and Revision Hints

( \frac{\frac{(n+3)!}{(n-2)!}}{\frac{(n+2)!}{(n-3)!}} ) का सरल रूप क्या है? / What is the simplified form of ( \frac{\frac{(n+3)!}{(n-2)!}}{\frac{(n+2)!}{(n-3)!}} )?

Correct Answer: A. \( \frac{n+3}{n-2} \). Explanation: दोनों बड़े अनुपातों के समान गुणक कट जाते हैं। अंत में \( \frac{n+3}{n-2} \) बचता है। / The common factors of both large ratios cancel out. Finally \( \frac{n+3}{n-2} \) remains.

Which concept should I revise for this Mathematics MCQ?

The common factors of both large ratios cancel out. Finally \( \frac{n+3}{n-2} \) remains.

What exam hint can help solve this Mathematics question?

दोनों बड़े अनुपातों के समान गुणक कट जाते हैं। अंत में \( \frac{n+3}{n-2} \) बचता है।