फलन \(y=7-\sqrt{x-1}\) की रेंज क्या है?
What is the range of \(y=7-\sqrt{x-1}\)?
Explanation opens after your attempt
A. (\(-\infty,7]\)
Concept
Since \(\sqrt{x-1}\ge 0\), \(7-\sqrt{x-1}\le 7\). The values can decrease without bound.
Why this answer is correct
The correct answer is A. (\(-\infty,7]\). Since \(\sqrt{x-1}\ge 0\), \(7-\sqrt{x-1}\le 7\). The values can decrease without bound.
Exam Tip
\(\sqrt{x-1}\ge 0\) है इसलिए \(7-\sqrt{x-1}\le 7\) होता है। मान नीचे की ओर असीमित जा सकते हैं।
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